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A box contains 20 balls: 10 are yellow , 6 are red and 4 are grey. What is the probability of picking a yellow and then a red ball without replacing the first

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Answer:

3/19

Step-by-step explanation:

A box contains 20 balls: 10 are yellow , 6 are red and 4 are grey.

P(yellow) = yellow balls / total balls

         = 10/20 = 1/2

Now there are only  19 balls: 9 are yellow , 6 are red and 4 are grey.

P(red) = red balls/ total

          =6/19

Multiply the two probabilites together

P(yellow) * P(red) = 1/2 * 6/19 = 3/19

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