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If an object is dropped from the height of 54 feet,
the function h = -16t² + 54 gives the height of the object after
t seconds.
Approximately how long will it take before the object hits the ground?

a. 2.45
b. 1.84
c. 1.30
d. 0.75

Respuesta :

Answer:

b

Step-by-step explanation:

When the object hits the ground , the h = 0 , that is

- 16t² + 54 = 0 ( subtract 54 from both sides )

- 16t² = - 54 ( divide both sides by - 16 )

t² = [tex]\frac{54}{16}[/tex] ( take square root of both sides )

t = [tex]\sqrt{\frac{54}{16} }[/tex] ≈ 1.84 seconds ( to 2 dec. places )

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