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Find the equation of the line that is perpendicular to line
6x-5y-6= 0 and passes through the point A(6,10).

Respuesta :

sqdancefan

Answer:

  5x +6y -90 = 0

Step-by-step explanation:

The perpendicular line will have the x- and y-coefficients swapped, and one of them negated. The constant will be chosen so the equation is satisfied at the given point.

  5x +6y = 5(6) +6(10) = 90

The equation of the perpendicular line in general form is ...

  5x +6y -90 = 0

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