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Calcium carbonate reacts with lithium metal to result in a single replacement reaction.
How many grams of each product are formed from 25.0 grams of lithium metal?

Respuesta :

Oseni

133.0 grams and 72.0 grams of Li2CO3 and Ca would be formed respectively.

From the equation of the reaction:

[tex]2 Li + CaCO_3 ---> Li_2CO_3 + Ca[/tex]

The mole ratio of Li to Li2CO3 is 2:1 while that of Li to Ca is also 2:1.

Mole of 25.0 grams of Li = mass/molar mass

                                        = 25/6.94

                                           = 3.6 moles

Equivalent of mole of Li2CO3 = 3.6/2

                                                  = 1.8 moles

  • Amount of Li2CO3 formed = mole x molar mass

                                              = 1.8 x 73.89

                                              = 133 grams

Equivalent mole of Ca = 3.6/2

                                   = 1.8 moles

  • Amount of Ca formed = 1.8 x 40

                                    = 72 grams

More on stoichiometric calculations can be found here: https://brainly.com/question/2563006?referrer=searchResults

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