is anyone good at math and can help with this, or at least the first one and explain how to do it?

now, bear in mind that all these ones are lines, and to graph a line all you need is two points, so let's pick a couple of random values for say "x" and let's see what we get for "y" and that's our x,y point.
3)
[tex]9x+4y=-16\implies \stackrel{\textit{using x = 0}~\hfill }{9(0)+4y=-16}\implies 4y=-16 \\\\\\ y=\cfrac{-16}{4}\implies y=-4~\hspace{10em}(0~~,~~-4) \\\\[-0.35em] ~\dotfill\\\\ 9x+4y=-16\implies \stackrel{\textit{using x = -4}~\hfill }{9(-4)+4y=-16}\implies -36+4y=-16 \\\\\\ 4y=20\implies y = \cfrac{20}{4}\implies y = 5~\hspace{10em}(-4~~,~~5)[/tex]
check the red line in the picture below.
4)
[tex]5x+2y=8\implies \stackrel{\textit{using x = 0}~\hfill }{5(0)+2y=8}\implies 2y=8\implies y=\cfrac{8}{2}\implies y=4 \\\\\\ ~\hspace{10em}~\hspace{10em}(0~~,~~4) \\\\\\ 5x+2y=8\implies \stackrel{\textit{using x = 4}~\hfill }{5(4)+2y=8}\implies 20+2y=8\implies 2y=-12 \\\\\\ y=\cfrac{-12}{2}\implies y=-6~\hspace{10em}(4~~,~~-6)[/tex]
check the blue line in the picture below.