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Quiz
Question 1 (5 points)
Find all real and non-real roots of the function ƒ(x) = (x2 + 4)(x – 2).
Question 1 options:

A)

x = ±2

B)

x = ±2i

C)

x = ±4i, 2

D)

x = ±2i, 2
Question 2 (5 points)
Which of the following lists the roots of ƒ(x) = x3 + x2 + 3x + 3?
Question 2 options:

A)

x = ±1.73i, –1

B)

x = ±1.73, 1

C)

x = ±1.73i, 1

D)

x = ±1.73, –1

Respuesta :

Answer:

D, D

Step-by-step explanation:

We have that,

[tex]( {x}^{2} + 4)(x - 2)[/tex]

Sk we just set each factor equal to zero.

[tex]{x}^{2} + 4 = 0[/tex]

[tex] {x}^{2} = - 4[/tex]

[tex] {x = \sqrt{ - 4} [/tex]

[tex]x = 2i[/tex]

oe

[tex]x = - 2i[/tex]

Then we set the final equal to zero.

[tex](x - 2) = 0[/tex]

[tex]x = 2[/tex]

So D is the answer.

[tex](x + 1[/tex]

is a root so that means that

[tex](x + 1)( {x}^{2} + 3)[/tex]

Are the roots.

We set

[tex]x + 1 = 0[/tex]

[tex] {x}^{2} + 3 = 0[/tex]

[tex]x = - 1[/tex]

[tex]x = \sqrt{ - 3} [/tex]

Which is about 1.73. so

D is the answer

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