A bird takes off from the roof of a 250-foot-tall building and flies to the ground below. Its path
takes the form of a parabola. The bird’s height can be modeled by h(t) = –t2 + 15t + 250, where
h(t) is the height of the bird above ground in feet t seconds after leaving the roof. After how
many seconds does the bird land on the ground?

Respuesta :

The bird on the roof  of a 250 ft building landed on the ground after 25 seconds

The height of the bird is modelled as follows:

h(t) = -t² + 15t + 250

h(t) = height of the bird above the ground(ft)

t = time in seconds after leaving the roof.

Therefore, the time in seconds the bird land after leaving the roof can be calculated as follows:

h(t) = -t² + 15t + 250

0 =  -t² + 15t + 250

0 = -t² + 15t + 250

t² - 15t - 250 = 0

Using quadratic formula,

a = 1

b = -15

c = -250

t = -b ±√b² - 4ac  / 2a

t = -b ± √(-15)² - 4(1)(-250) / 2 × 1

t = 15 ± √225 + 1000 / 2

t = 15 ± √ 1225 / 2

t = 15 ± 35 / 2

t = 15 - 35 / 2   or t = 15 + 35 / 2

t = -20 / 2 or 50 / 2

t = -10 or 25

The time can't be negative.

Therefore, the bird landed on the ground after 25 seconds.

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