Using the Poisson distribution, it is found that P(X = 1) = 0.3599.
We have only the mean, hence, the Poisson distribution is used to solve this question.
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:
[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]
The parameters are:
In this problem, the mean is of 0.0864 failures per 100 miles per day, that is, 0.0864 failures per 161 km, hence, per 1500 km:
[tex]\mu = \frac{1500}{161} \times 0.0864 = 0.8053[/tex]
Then:
[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]
[tex]P(X = 1) = \frac{e^{-0.8053}(0.8053)^{1}}{(1)!} = 0.3599[/tex]
To learn more about the Poisson distribution, you can take a look at https://brainly.com/question/13971530