The new speed of the glider is 42.2 m/s.
The new speed of the glider can be calculated using the principle of the law of conservation of energy.
Note: Total energy of the glider before the dive = Total energy of the glider after the dive.
Formula:
- mv²/2+mgh = mV²/2 +mgH................ Equation 1
Simplifying the equation above,
make V the subject of the equation.
- V = √[(v²/2)+gh]-gH]............... Equation 2
Where:
- V = New speed of the glider
- v = initial speed of the glider
- h = initial height of the glider
- H = New height of the glider
- g = acceleration due to gravity.
From the question,
Given:
- v = 40 m/s
- h = 300 meters
- H = 200 meters
- g = 9.8 m/s²
Substitute these values into equation 2.
- V = √[(40²/2)+(9.8×300)-(9.8×200)]
- V = √(800+2940-1960)
- V = √1780
- V = 42.2 m/s.
Hence, The new speed of the glider is 42.2 m/s.
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