The factorized form of 2y² - 5y + 2 is (2y - 1) (y - 2)
Factorization
Given:
= 2y² - 4y - y + 2
= 2y(y - 2) - 1(y - 2)
= (2y - 1) (y - 2)
= 5x² - 5x + 7x - 7
= 5x(x - 1) + 7(x - 1)
= (5x + 7) (x - 1)
- The value of x for which 5x² + 2x - 7 = 0
5x² + 2x - 7 = 0
5x² - 5x + 7x - 7 = 0
5x(x - 1) + 7(x - 1) = 0
(5x + 7) (x - 1) = 0
5x + 7 = 0 or x - 1 = 0
5x = - 7 or x = 1
x = -7/5 or x = 1
Therefore, the value of x for which 5x² + 2x - 7 = 0 is -7/5 or 1
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