The magnitude of the average total force acting on the object during this time interval is equal to 20 Newton.
Given the following data:
To calculate the magnitude of the average total force acting on the object during this time interval:
In order to solve for the force acting on the dummy, we would apply Newton's Second Law of Motion.
Note: The acceleration of an object is equal to the rate of change in velocity with respect to time.
Mathematically, Newton's Second Law of Motion is given by this formula;
[tex]F = \frac{M(v\;-\;u)}{t}[/tex]
Substituting the given parameters into the formula, we have;
[tex]F_A = \frac{2(30\;-\;0)}{5}\\\\F_A = \frac{2\times 30}{5}\\\\F_A = \frac{60}{5}[/tex]
Force A = 12 Newton.
For the second force:
[tex]F_B = \frac{2(40\;-\;0)}{5}\\\\F_B = \frac{2\times 40}{5}\\\\F_B = \frac{80}{5}[/tex]
Force B = 16 Newton.
Now, we can calculate the magnitude of the average total force acting on the object during this time interval:
[tex]F = \sqrt{F_A^2 + F_B^2} \\\\F = \sqrt{12^2 + 16^2}\\\\F = \sqrt{144 + 256}\\\\F=\sqrt{400}[/tex]
Total force = 20 Newton.
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