The height reached by the object above the ground is 11.5 m.
The given parameters:
- Mass, m = 2 kg
- Speed of the object, v = 15 m/s
What is principle of conservation of energy?
- The principle of conservation of energy states that, the total energy of a system is always conserved.
P.E = K.E
mgh = ¹/₂mv²
gh = ¹/₂v²
[tex]h = \frac{v^2}{2g} \\\\h = \frac{(15)^2}{2(9.8)} \\\\h = 11.5 \ m[/tex]
Thus, the height reached by the object above the ground is 11.5 m.
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