Respuesta :

LammettHash

cos²(x) = 3 sin²(x)

1 - sin²(x) = 3 sin²(x)

1 = 4 sin²(x)

1/4 = sin²(x)

± √(1/4) = sin(x)

± 1/2 = sin(x)

sin(x) = 1/2   or   sin(x) = -1/2

[x = arcsin(1/2) + 2nπ   or   x = π - arcsin(1/2) + 2nπ]

… … … or   [x = arcsin(-1/2) + 2nπ   or   x = π - arcsin(-1/2) + 2nπ]

(where n is any integer)

[x = π/6 + 2nπ   or   x = 5π/6 + 2nπ]

… … … or   [x = -π/6 + 2nπ   or   x = 7π/6 + 2nπ]

okpalawalter8

For a trigonometric equation. Cos^2x=3sin^2x, the solution is mathematically given as

x = π/6 + 2nπ

What is the solution of the trigonometric equation?

Generally, the equation for the trigonometric equation is mathematically given as

Cos^2x=3sin^2x

Therefore

1 - sin^2(x) = 3 sin^2(x)

1/4 = sin^2(x)

Hence introducing \pi

x = arcsin(1/2) + 2nπ  

x = π/6 + 2nπ

In conclusion,

x = π/6 + 2nπ

Read more about trigonometric

https://brainly.com/question/14746686

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