The width of a rectangle is a whole number of centimetres. a The length of the rectangle is 9 cm longer than its width. The perimeter of the rectangle is less than 200 cm. Find the greatest possible width of the rectangle.

Answer:
let w = the width of the rectangle
let w- 9=the length of the rectangle
A= L×W
220=w(w-9)
220=w^-9w
w^-9w-220=0
(w-20)(w+11)=0
w-20=0 or w+11=0
w=20cm or x-11 illogical answer