The ionization energy of silver is 731 kJ/mol. Is light with a wavelength of 415 nm sufficient to remove an electron from a silver atom in the gaseous phase?

Respuesta :

The energy of the light with a wavelength of 415 nm is not sufficient to remove an electron from a silver atom in the gaseous phase.

Energy and wavelength of light

The energy and wavelength of light are related by the formula given below:

  • Energy = hc/λ
  • where, E = energy
  • h = Planck's constant
  • c = velocity of light
  • λ = wavelength of light

Calculating the energy of the light

From the data provided:

  • h = 6.63 × 10^-34 Js
  • c = 3.0 × 10^8 m/s
  • λ = 415 nm = 4.15 × 10^-7 m

E = (6.63 × 10^-34 × 3.0 × 10^8 m/s)/4.15 × 10^-7 m

E = 4.79 × 10^-19 J

Energy of light is 4.79 × 10^-19 J

Compared with the ionization energy of silver, the energy of the light is far less.

Therefore, the energy of the light with a wavelength of 415 nm is not sufficient to remove an electron from a silver atom in the gaseous phase.

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