Answer:
Step-by-step explanation:
y = mx +b
Here m is slope and b is y-intercept
y = -2x + 1
We've been given to find out the equation of a line who has its slope (m) = -2 and a Y-intercept = 1. So here we have basically two things i.e,
First of all we must know the unique form of equation of line which is y = mx + c which is only applicable for those who have slope and y-intercept defined in it.
Placing respective values,
[tex]:\implies\rm{y = mx + c}[/tex]
[tex]:\implies\rm{y = - 2x + 1}[/tex]
1) Slope point form equation: If a line passes through point (x,y) and slope (m) then equation of line is given by,
[tex]:\implies\rm{ y - y_1 = m(x - x_1)}[/tex]
2) Two point form equation: If a line passes through two distinct points A(x1,y1) and B(x2,y2) then equation of line is given by,
[tex]:\implies\rm{ \frac{y - y_1}{y_1 - y_2} = \frac{x - x_1}{x_1 - x_2} }[/tex]
3) Double intercept form: If x & y intercepts of line are small 'a' and 'b' then equation of line is given by,
[tex]:\implies\rm{ \frac{x}{a} + \frac{y}{b} = 1}[/tex]
