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Using your (Q heat) answer from the last problem calculate (C) the specific heat
of the metal. The initial temperature of the metal is 100 C which cooled to a final
system temperature of 50 C when place in the water.. The mass of the metal is 25
grams.
*
8.36 J/gºC
5.0 J/gºC
12.0 J/gºC
69.88 J/gºC

Respuesta :

sebassandin

This problem is asking for the specific heat of 25 g of a metal which was cooled from 100 °C to 50 °C. Now, since you provided the correct choice, 8.36 J/gºC, the heat giving such result must have been -10,450 J, and thus, the procedure for finding the required is shown down below:

Calorimetry:

In chemistry, we widely use calorimetry to relate the mass, specific heat, temperature change and heat during a heating or a cooling process, according to the following equation:

[tex]Q=mC(T_f-T_i)[/tex]

Now, considering the aforementioned, one can plug in the heat, mass and temperatures to obtain:

[tex]-10,450J=25g*C*(50\°C-100\°C)[/tex]

For us to solve now for the specific heat, C, as follows:

[tex]C=\frac{-10,450J}{25g*(50\°C-100\°C)} =8.36\frac{J}{g\°C}[/tex]

However, note this work can also be applied to any other given heat if needed.

Learn more about calorimetry: https://brainly.com/question/1407669

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