Respuesta :
Considering the reaction stoichiometry and the definition of molarity, the correct answer is option B. 1.6 liters of 3.0 M NaOH solution will react with 2.4 mol H₂SO₄.
The balanced reaction is:
H₂SO₄ + 2 NaOH → Na₂SO₄ + 2 H₂O
Reaction stoichiometry
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- H₂SO₄: 1 mole
- NaOH: 2 moles
- Na₂SO₄: 1 mole
- H₂O: 2 moles
Then you can apply the following rule of three: If by stoichiometry 1 mole of H₂SO₄ reacts with 2 moles of NaOH, 2.4 moles of H₂SO₄ react with how many moles of NaOH?
[tex]amount of moles of NaOH=\frac{2.4 moles of H_{2}SO_{4}x2 moles of NaOH }{1 mole of H_{2}SO_{4}}[/tex]
amount of moles of NaOH= 4.8 moles
Molarity
On the other side, molarity is the number of moles of solute that are dissolved in a certain volume and is determined by the following expression:
[tex]molarity=\frac{number of moles of the solute}{volume}[/tex]
Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].
In this case, you know:
- molarity= 3 M= 3 [tex]\frac{moles}{liter}[/tex]
- number of moles of the solute= 4.8 moles
- volume= ?
Replacing:
[tex]3\frac{moles}{liter} =\frac{4.8 moles}{volume}[/tex]
Solving:
3 [tex]\frac{moles}{liter}[/tex]× volume= 4.8 moles
volume= 4.8 moles÷ 3 [tex]\frac{moles}{liter}[/tex]
volume= 1.6 liters
Finally, the correct answer is option B. 1.6 liters of 3.0 M NaOH solution will react with 2.4 mol H₂SO₄.
Learn more about:
- reaction stoichiometry:
- https://brainly.com/question/11999193
- molarity with this example:
- brainly.com/question/15406534?referrer=searchResults
Answer:
B. 1.6 L
Explanation:
Guy above me is right. I took the test :)
