The linear speed of the hammer in feet per second is 109.27 ft/s
Since the athlete completes the last revolution in t = 0.23 seconds and 1 revolution = 2π, the angular speed of the hammer, ω = 2π/t = 2π/0.23 = 27.32 rad/s.
Now, the linear speed v = rω where
So, substituting these into the equation for v, we have
v = rω
v = 4 ft × 27.32 rad/s
v = 109.27 ft/s
So, the linear speed of the hammer in feet per second is 109.27 ft/s
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