The savings in a bank account can be modeled using S = 1250e^0.45t, where t is the number of years the
money has been in the account. Determine, to the nearest tenth of a year, how long it will take for the
amount of savings to double from the initial amount deposited of $1250?

Respuesta :

Using the given exponential function, it is found that it will take 1.5 years for the  amount of savings to double from the initial amount deposited of $1250.

Exponential function:

The exponential function that models the savings in the bank account is given by:

[tex]S(t) = 1250e^{0.45t}[/tex]

  • In which t is the time in years that the money has been in the account.

The time to double from the initial amount deposited of $1250 is t for which S(t) = 2(1250) = 2500, hence:

[tex]S(t) = 1250e^{0.45t}[/tex]

[tex]2500 = 1250e^{0.45t}[/tex]

[tex]e^{0.45t} = \frac{2500}{1250}[/tex]

[tex]e^{0.45t} = 2[/tex]

[tex]\ln{e^{0.45t}} = \ln{2}[/tex]

[tex]0.45t = \ln{2}[/tex]

[tex]t = \frac{\ln{2}}{0.45}[/tex]

[tex]t = 1.5[/tex]

It will take 1.5 years for the  amount of savings to double from the initial amount deposited of $1250.

To learn more about exponential functions, you can take a look at https://brainly.com/question/14855561