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[tex]\qquad[/tex]❄️[tex]\boxed{\bf x = 7}\\\\[/tex]

We are given –

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf 8x -2 y =48[/tex]

  • And also value of y's given. So, just put the value of y in the given equation.

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[tex]\qquad[/tex] [tex]\purple{\twoheadrightarrow\bf 8x -2 y =48}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf 8x - \underbrace{2 \times 4} =48 [/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf 8x - 8 =48[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf 8x = 48 +8[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf 8x = 56[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf x =\cancel{\dfrac{56}{8}}[/tex]

[tex]\qquad[/tex] [tex]\purple{\twoheadrightarrow\bf x= 7}[/tex]

  • Henceforth, value of x is 7.

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Amphitrite1040

Hey there!

8x - 2y = 48

8x - 2(4) = 48

8x - 8 = 48

ADD 8 to BOTH SIDES

8x - 8 + 8 = 48 + 8

CANCEL out: -8 + 8 because it give you 1

KEEP: 48 + 8 because it help solve for the x-value

NEW EQUATION: 8x = 48 + 8

SIMPLIFY IT!

8x = 56

DIVIDE 8 to BOTH SIDES

8x/8 = 56/8

CANCEL out: 8/8 because it give you 1

KEEP: 56/8 because it help solve for the x-value

NEW EQUATION: x = 56/8

SIMPLIFY IT!

x = 7

Therefore, your answer is: x = 7

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

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