Answer:
Overall, the electric charge of the compound [tex]{\rm NaOH}[/tex] is [tex]0[/tex].
Explanation:
Sodium hydroxide [tex]{\rm NaOH}[/tex] is an ionic compound. This compound is made up of a large number of sodium ions [tex]{\rm Na^{+}}[/tex] and hydroxide ions [tex]{\rm OH^{-}}[/tex].
As the superscripts suggest, each sodium ion [tex]{\rm Na^{+}}[/tex] carries a charge of [tex](+1)[/tex] while each hydroxide ion [tex]{\rm OH^{-}}[/tex] carries a charge of [tex](-1)[/tex].
The two types of ions are paired up at a one-to-one ratio within [tex]{\rm NaOH}[/tex]. Charges on these ions would balance one another, such that the overall electric charge on the compound [tex]{\rm NaOH}\![/tex] would be [tex]0[/tex].
