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HELP PLEASEEEE

b. Calculate the empirical formula of a molecule with the following percent
compositions: 55.0% gallium (Ga) and 45.0% fluorine (F). Complete the table below to help with the calculations. Round off all calculations to the nearest
tenth. (5 points)

HELP PLEASEEEE b Calculate the empirical formula of a molecule with the following percent compositions 550 gallium Ga and 450 fluorine F Complete the table belo class=

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unknown767

Explanation:

So first find out the moles. The percentage is out of 100 so just convert the percentage into mass by just changing the sign.

Ga = 55g/69.7 = 0.789 moles

F=45g/19 = 2.37 moles

Then divide by smallest value to find out the formula

Ga=0.789÷0.789= 1

F=2.37÷0.789 = 3

GaF3

hope this helps:)

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