The function F(x) have a vertical asymptote at x =0 and x =1.
Given that
The given Function;
[tex]\rm F(x)=\dfrac{2}{3x(x-1)(x^ 5)}[/tex]
We have to determine
At which value the function F(x) has a vertical asymptote.
According to the question
The given Function;
[tex]\rm F(x)=\dfrac{2}{3x(x-1)(x^ 5)}[/tex]
The function is undefined when the denominator becomes 0. Find values of x for which the denominator is 0:
Then,
[tex]\rm 3x (x-1) (x^5)= 0[/tex]
[tex]\rm x^5 =0, \ \ x=0\\\\ x-1 = 0, \ \ x =1\\[/tex]
The value of x is 0 and 1.
Hence, the function F(x) have a vertical asymptote at x =0 and x =1.
To know more about Parabola click the link given below.
https://brainly.com/question/12868913
