Combinations
She can make 16 different combinations to reach the desired amount.
Given that Dolores has 6 quarters, 5 dimes, 4 nickels and 10 pennies, to determine how many different combination of coins can she make to have 0.50 cents, the following calculation must be performed:
- 0.25 x 2 = 0.50
- 0.25x1 + 0.10x2 + 0.05x1 = 0.50
- 0.25 x 1 + 0.10 x 2 + 0.01 x 5 = 0.50
- 0.25x1 + 0.10x1 + 0.05x3 = 0.50
- 0.25x1 + 0.10x1 + 0.05x2 + 0.01x5 = 0.50
- 0.25x1 + 0.10x1 + 0.05x1 + 0.01x10 = 0.50
- 0.25 x 1 + 0.05 x 4 + 0.01 x 5 = 0.50
- 0.25 x 1 + 0.05 x 3 + 0.01 x 10 = 0.50
- 0.10 x 5 = 0.50
- 0.10 x 4 + 0.05 x 2 = 0.50
- 0.10 x 4 + 0.05 x 1 + 0.01 x 5 = 0.50
- 0.10 x 4 + 0.01 x 10 = 0.50
- 0.10 x 3 + 0.05 x 4 = 0.50
- 0.10x3 + 0.05x3 + 0.01x5 = 0.50
- 0.10 x 3 + 0.05 x 2 + 0.01 x 10 = 0.50
- 0.10x2 + 0.05x4 + 0.01x10 = 0.50
Therefore, she can make 16 different combinations to reach the desired amount.
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