Answer:
Approx.
300
⋅
m
g
Explanation:
We use the Ideal Gas Equation to access the molar quantity of dioxygen gas............
n
=
P
V
R
T
=
0.927
⋅
a
t
m
×
0.4981
⋅
L
0.0821
⋅
L
⋅
a
t
m
K
⋅
m
o
l
×
418.4
⋅
K
=
1.34
×
10
−
2
⋅
m
o
l
.
Given the stoichiometric equation..........
M
g
(
s
)
+
O
2
(
g
)
→
M
g
O
(
s
)
There are
1.34
×
10
−
2
⋅
m
o
l
×
24.31
⋅
g
⋅
m
o
l
−
1
=
?
?
⋅
g
metal required for stoichiometric equivalence.
