Answer:
No
Step-by-step explanation:
In every right triangle, [tex]a^{2} +b^2=c^2[/tex] where "a" and "b" are the legs of the right triangle and "c" is the hypotenuse (This is known as "Pythagorean's theorem). To figure out if a triangle with side lengths 6, 8, and 11 inches is a right triangle, all you have to do is plug in the values 6 and 8 for "a" and "b" and the value 11 for "c" to get":
[tex]6^2+8^2=11^2[/tex]
This simplifies to:
[tex]36+64=121[/tex]
Which simplifies further to:
[tex]100=121[/tex]
This is obviously incorrect so therefore, the triangle lengths given do not form a right triangle.
Hope this helps :)
Answer:
NO.
Step-by-step explanation:
If it is a right triangle then if h = longest side then by the inverse of Pythagoras Theorem:
h^2 = a^2 + b^2 (where a and b are other 2 sides).
So with the given values:
h^2 = 11^2 = 121
a^2 + b^2 = 6^2 + 8^2 = 36 + 64 = 100.
-not equal so NOT a right triangle.
