This question is providing two ions, Sn⁴⁺ and F¹⁻ so that the compound they form is asked to be named. At the end, according to the IUPAC rules, the name will be B: Tin (IV) fluoride.
In chemistry, nomenclature is used to assign the proper name of a chemical compound, so that it can be recognized in any part of the world. In this particular case, since this is a binary salt with a cation that has two oxidation states, Sn⁴⁺ and Sn²⁺, we should assign the correct roman numeral, which is tin (VI).
On the other hand, since fluorine takes a negative charge when forming binary salts, as a 1-, its assigned name would be fluoride. In such a way, by combining them, we find the name as B: Tin (IV) fluoride.
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