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A jeweler is determining the optical properties of an unknown blue gemstone. She uses an angle of incidence of 62°, and measures an angle of refraction of 30°. Assuming the index of refraction of air is 1. 0, what is the index of refraction of the gem?.

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ncsftw

Answer:

1.77

Explanation:

Snell's law:

[tex]\frac{n_1}{n_2} = \frac{sin(theta_2)}{sin(theta_1)} \\\\n_1 = 1.0\\n_2 = x\\theta_1 = 62\\theta_2 = 30\\\\n_2 = \frac{sin(theta_1)}{sin(theta_2)} * n_1\\n_2 = 1.76589 ... 1.77 (3 sig fig)[/tex]

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