The ball will reach it's maximum height after 65.98s
To solve this problem, we would use equation of time to attain maximum height under projectile motion.
T[tex]_m_a_x[/tex]= (Usinθ)/g
The data given are;
- H[tex]_o[/tex] = 6ft
- Initial speed/velocity (U) = 68 ft/s
- θ = 76°
Time to reach Maximum Height
[tex]T_m_a_x = u sinx\\T_m_a_x = 68sin76\\T_m_a_x = 65.98s[/tex]
The time it takes the ball to attain maximum height is 65.98s.
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