PLEASE HELP!!

A 91 kg fullback moving east with a speed of 5.0 m/s is tackled by a 95 kg opponent running west at 3.0 m/s, and the collision is perfectly inelastic.
Calculate the following:
a.) The velocity of the players just after the tackle
b.) The decrease in kinetic energy during the collision

Respuesta :

The velocity of the players just after the tackle is 0.91 m/s moving eastward and the decrease in kinetic energy is -1488 J

Linear momentum

The law of conservation of linear momentum states that:

Momentum before collision = momentum after collision

Hence:

  • m₁u₁ + m₂u₂ = (m₁ + m₂)v

Where m₁, m₂ are masses of the object, u₁, u₂ are the object initial velocity and v is the velocity of both objects after collision.

a)

  • m₁u₁ + m₂u₂ = (m₁ + m₂)v
  • 91(5) + 95(-3) = (91 + 95)v
  • v = 0.91 m/s

The velocity of the players just after the tackle is 0.91 m/s moving eastward.

b)

Initial kinetic energy = (1/2)(91)(5)² + (1/2)(95)(-3)² = 1565 J

Final kinetic energy = (1/2)(91 + 95)(0.91)² = 77 J

The decrease in kinetic energy = 77 - 1565 = -1488 J

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