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Tina has two bags of counters, Bag A and Bag B.
There are 5 red counters and 3 blue counters in bag A.
There are 4 red counters and 5 blue counters in bag B.
Tina takes at random a counter from each bag.
(a) Complete the probability tree diagram.

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francocanacari

The probability of getting two red counters is 27.77%, the probability of getting two blue counters is 20.38%, and the probability of getting one of each color is 51.38%.

Given that Tina has two bags of counters, Bag A and Bag B, and there are 5 red counters and 3 blue counters in bag A, while there are 4 red counters and 5 blue counters in bag B, to determine, if Tina takes at random a counter from each bag, the probability of obtaining each counter, the following calculation must be made:

  • Bag A red counter = 5/8 = 0.625
  • Bag A blue counter = 1 - 0.625 = 0.375
  • Bag B red counter = 4/9 = 0.444
  • Bag B blue counter = 1 - 0.444 = 0.555
  • Two red = 0.625 x 0.444 = 0.2777
  • Two blue = 0.375 x 0.555 = 0.2083
  • One red and one blue = 1 - 0.2777 - 0.2083 = 0.5138

Therefore, the probability of getting two red counters is 27.77%, the probability of getting two blue counters is 20.38%, and the probability of getting one of each color is 51.38%.

Learn more about probability in https://brainly.com/question/25638875

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