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A student performed an experiment to determine
the total amount of energy stored in a peanut.
The student measured 100.0 grams of water into
a metal can and placed the can on a ring stand, as
shown in the diagram below. The peanut was attached
to a wire suspended under the can. The initial
temperature of the water was recorded as 32.0°C. The
peanut was ignited and allowed to burn. When the
peanut finished burning, the final water temperature was recorded as 57.0 °C

A student performed an experiment to determine the total amount of energy stored in a peanut The student measured 1000 grams of water into a metal can and place class=

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Eduard22sly

The total amount of heat absorbed by the water is 10460 J.

Determination of the change in the temperature of the water.

  • Initial temperature (T₁) = 32 °C
  • Final temperature (T₂) = 57 °C
  • Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 57 – 32

ΔT = 25 °C

Determination of the heat absorbed by the water

  • Mass of water (M) = 100 g
  • Change in temperature (ΔT) = 25 °C
  • Specific heat capacity of water = 4.184 J/gºC
  • Heat absorbed (Q) =?

Q = MCΔT

Q = 100 × 4.184 × 25

Q = 10460 J

Thus, the heat energy absorbed by the water is 10460 J

Learn more about heat transfer:

https://brainly.com/question/25823870

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