The final temperature of the liquids is 43.45°C
Given data:
The mass of water is, m = 15.00 g.
The specific heat capacity of water is, c = 4.186 J.
The initial temperature of water of mass m is, T = 66°C.
The extra mass of water added is, m' = 40.00 g.
The temperature of the water added is, T' = 35°C.
Here the concept of thermal equilibrium can be applied. The mass of water m will gain some while adding the water of mass m'. Then the final temperature of the liquid is expressed as,
[tex]T_{f}=\dfrac{(T \times m + T' \times m')}{m+m'}[/tex]
Solving as,
[tex]T_{f}=\dfrac{(66 \times 15 + 35 \times 40)}{15+40}\\\\T_{f}=43.45^{\circ} \; \rm C[/tex]
Thus, we can conclude that the final temperature of the liquids is 43.45°C.
Learn more about the thermal equilibrium here:
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