The profit function POs = (300 - Q)Q - 10Q
Profit = revenue - cost
Revenue = price × quantity = PQ = (300 - Q)Q
cost = maginal cost × quantity = 10Q
So, Profit, PO = revenue - cost
= (300 - Q)Q - 10Q
So, the profit function POs = (300 - Q)Q - 10Q
The level of diamond production sreeb chooses is Q = 185.
Since the profit function POs = (370 - Q)Q the level of diamond that will produce maximum profit is obtained when we differentiate POs with respect to Q and equate it to zero.
So, dPOs/dQ = d(370 - Q)Q/dQ
= (370 - Q)dQ/dQ + Qd(370 - Q)/dQ
= 370 - Q - Q
= 370 - 2Q
Equating it to zero, we have
370 - 2Q = 0
2Q = 370
Q = 370/2
Q = 185
The level of diamond production Sreeb chooses is Q = 185.
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