[tex] \sqrt{33 + \sqrt{4 + \sqrt{50 \cos(60°) } } } [/tex]
- Now, we know cos(60°) = [tex]\frac {1}{2}[/tex]. So put the value there.
[tex] \sqrt{33 + \sqrt{4 + \sqrt{50 \times \frac{1}{2} } } } \\ = \sqrt{33 + \sqrt{4 + \sqrt{25} } } \\ = \sqrt{33 + \sqrt{4 + 5 } } \\ = \sqrt{33 + \sqrt{9} } \\ = \sqrt{33 + 3} \\ = \sqrt{36} \\ = 6[/tex]
Hence LHS = RHS [Proved]
Hope you could understand.
If you have any query, feel free to ask.
