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What is the equation of a line with points (16,-4) and (-32-10) Oy - 4= 1 (x - 16) Oy+4= 1 (x – 16) Oy - 10 = 3 (x – 32) O y + 10 = 1 (x + 32)​

What is the equation of a line with points 164 and 3210 Oy 4 1 x 16 Oy4 1 x 16 Oy 10 3 x 32 O y 10 1 x 32 class=

Respuesta :

mhanifa

Answer:

  • D. y + 10 = 1/8* (x + 32)

Step-by-step explanation:

Use the given points to work out the equation of the line.

Find the slope:

  • m = (- 10 - (-4)) / (- 32 - 16) = - 6 / - 48 = 1/8

Use (-32, - 10) and point- slope form:

  • y - (- 10) = 1/8*(x - (-32))
  • y + 10 = 1/8* (x + 32)

Correct choice is D

Points

  • (16,-4)
  • (-32,-10)

Equation of line in two points form

[tex]\\ \sf\longmapsto y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

[tex]\\ \sf\longmapsto y+10=\dfrac{-10+4}{-32-16}(x+32)[/tex]

[tex]\\ \sf\longmapsto y+10=\dfrac{-6}{-48}(x+32)[/tex]

[tex]\\ \sf\longmapsto y+10=\dfrac{1}{8}(x+32)[/tex]

Option D

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