The diagram shows the parts of a right triangle with an altitude to the hypotenuse. For the two given measures, find the other four.

The values of a, s1, s2, is equal to 11 and the value of u1 and u2 is equal 15.6.
Data Given;
To solve this problem, we have to use some basic formulas in right-angle triangle such as trigonometric ratios and Pythagoreans theorem.
[tex]h = s_1 + s_2\\ s_1 = 11\\ h = 22\\ 22 = 11 + s_2\\ s_2 = 22 - 11\\ s_2 = 11[/tex]
On the top of the triangle, we have another right-angle divided into two. This makes each side equal 90/2 = 45 degrees
Using trigonometric ratio SOHCAHTOA
We can solve for a using tangent of the angle
[tex]tan45 = \frac{11}{a}\\ a = \frac{11}{tan45}\\ a = 11[/tex]
The length of a is equal 11.
using the length of a, we can solve for u1 or u2 using Pythagorean theorem.
[tex]u_1^2 = a^2 + s_2\\ u_1^2 = 11^2 + 11^2\\ u_1^2 = 242\\ u_1 = \sqrt{242}\\ u_1 = 15.6[/tex]
Solving for u2
[tex]u_2^2 = a^2 + s_2^2\\ u_2^2 = 11^2 + 11^2\\ u_2^2= 242\\ u_2 = \sqrt{242}\\ u_2 = 15.6[/tex]
From the calculations above, the values of a, s1, s2, is equal to 11 and the value of u1 and u2 is equal 15.6.
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