A. The maximum possible mass of sodium that can be produced is 47.18 Kg
B. The percentage yield of the reaction is 80.6%
We'll begin by calculating the mass of NaCl that reacted and the mass of Na obtained from the balanced equation.
2NaCl –> 2Na + Cl₂
Molar mass NaCl = 23 + 35.5 = 58.5 g/mol
Mass of NaCl from the balanced equation = 2 × 58.5 = 117 g = 117 / 1000 = 0.117 Kg
Molar mass of Na = 23 g/mol
Mass of Na from the balanced equation = 2 × 23 = 46 g = 46 / 1000 = 0.046 Kg
SUMMARY
From the balanced equation above,
0.117 Kg of NaCl reacted to produce 0.046 Kg of Na.
From the balanced equation above,
0.117 Kg of NaCl reacted to produce 0.046 Kg of Na.
Therefore,
120 Kg of NaCl will react to produce = (120 × 0.046) / 0.117 = 47.18 Kg of Na
Thus, the maximum mass of Na produced is 47.18 Kg.
Percentage yield = (Actual / Theoretical) × 100
Percentage yield = (38.05 / 47.18) × 100
Percentage yield = 80.6%
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