Respuesta :

  • Width be x
  • Length be 2x

ATQ

[tex]\\ \tt\hookrightarrow Perimeter=88[/tex]

[tex]\\ \tt\hookrightarrow 2(x+2x)=88[/tex]

[tex]\\ \tt\hookrightarrow 2(3x)=88[/tex]

[tex]\\ \tt\hookrightarrow 6x=88[/tex]

[tex]\\ \tt\hookrightarrow 3x=44[/tex]

[tex]\\ \tt\hookrightarrow x=44/3\approx 15[/tex]

  • Width=15
  • Length=2(15)=30

Answer:

  • L = 88/3 units
  • W = 44/3 units

Step-by-step explanation:

We know that:

  • Perimeter of rectangle: 88
  • L = 2w

Solution:

  • 2(L) + 2(w) = 88 units
  • => 2(2w) + 2(w) = 88 units
  • => 4w + 2w = 88 units
  • => 6w = 88 units
  • => w = 88/6 units
  • => L = 2w
  • => L = 2(14 2/3)
  • => L = 2(44/3)
  • => L = 88/3 units

Hence, the dimensions of the rectangle is:

  • L = 88/3 units
  • W = 44/3 units