The different group of 2 players that the coach can pick is 45 groups.
The selection of groups of 2 player can be done using the method of combination.
The different group of 2 players that the coach can pick from the 10 players is calculated as follows;
n = 10C2
[tex]n = \frac{10!}{(10-2)! 2!} = \frac{10 \times 9\times 8!}{8! \times 2} = 45[/tex]
Thus, the different group of 2 players that the coach can pick is 45 groups.
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