Answer:
[tex] \huge{ \red{ \bold{SOLUTION:-}}}[/tex]
[tex] \rm{The \: sum \: of \: all \: the \: angles = 90 {}^{ \circ} }[/tex]
[tex] \rm{i.e.(8 {x}^{ \circ} ) + ( {6x}^{ \circ} + {6}^{ \circ} ) = {90}^{ \circ} }[/tex]
[tex] \implies{ \rm{ {14}^{ \circ} + {6}^{ \circ} = 90}}[/tex]
[tex] \implies{ \rm{ {14}^{ \circ} = {90}^{ \circ} - {6}^{\circ} }}[/tex]
[tex] \implies{ \rm{14x {}^{ \circ} = {84}^{\circ} }}[/tex]
[tex] \implies{ \displaystyle\rm{ {x}^{\circ} = \frac{8 {4}^{\circ} }{14} }}[/tex]
[tex] \implies{ \rm{ {x}^{\circ} = {6}^{\circ} }}[/tex]
[tex] \therefore{ \rm{The \: value \: of \: x \: is \: {6}^{ \circ} .}}[/tex]
[tex]\red {\rule{35pt}{2pt}} \green{ \rule{35pt}{2pt}}\orange{ \rule{35pt}{2pt}}\pink{ \rule{35pt}{2pt}}\blue{ \rule{35pt}{2pt}}\purple{ \rule{35pt}{2pt}}\red{ \rule{35pt}{2pt}}[/tex]
Hope this helps you....
