Given :-
- Two triangles with their two angles equal .
To Find :-
Answer :-
Here in ∆ABC and ∆EDC ,
- [tex]\angle[/tex] CAB = [tex]\angle[/tex]CED (given )
- [tex]\angle[/tex] CBA = [tex]\angle[/tex]CDE (given)
Therefore by AA similarity criterion , we can say that ∆ABC ~ ∆EDC . Also we know that corresponding sides of similar triangles are proportional . So ,
→ AC/EC = BC/DC
→ AC/9 = 8/12
→ AC = 8/12 * 9
→ AC = 6
Hence the measure of side AC is 6 .
I hope this helps.
