Answer:
to answer the first part of the question.
what is the velocity after 5s.
a=(v-u)/t
a=10m/s²
u=0m/s( initial velocity)
t=5s
10m/s²=(v-0m/s²)/5s
10m/s²×5s=v-0m/s²
50m/s=v
the velocity after 5s will be 50m/s
to answer the second question we use the newton's second equation of linear motion, that is
S=(displacement)
S=ut+0.5at²
S=0m/s²×5s+0.5×10m/s²×(5s)²
S=0.5×10m/s²×(5s)²
S=5m/s²×(25s²)
S=125m
it had fallen 125m from where it was thrown.
HOPE IT HELPED,
PLEASE MARK BRAINLIEST
