The magnitude of Tom's acceleration is 0.585 m/s².
Acceleration is the rate of change of velocity with time.
The force applied by the Tom's sister is calculated by applying Newton's second law of motion as follows;
F = ma
F = 15 x 2.3
F = 34.5 N
The acceleration of Tom is calculated by applying Newton's third law of motion as follows;
[tex]F_{Tom} = -F_{little \ sister}\\\\F_{Tom} = - 34.5 \ N[/tex]
[tex]a = \frac{F}{m} \\\\a = \frac{-34.5}{59} \\\\a = -0.585 \ m/s^2\\\\|a| = 0.585 \ m/s^2[/tex]
Thus, the magnitude of Tom's acceleration is 0.585 m/s².
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