Answer:
[tex]\ \ \ \ \ \ a_n=8+9(n-1)\\\implies a_n=8+9n-9\\\implies a_n=9n-1[/tex]
Step-by-step explanation:
arithmetic sequence equation:
[tex]a_n=a+(n-1)d[/tex]
where a is the first term and d is the common difference
Therefore,
[tex]\ \ \ \ \ \ a_n=8+9(n-1)\\\implies a_n=8+9n-9\\\implies a_n=9n-1[/tex]
