Respuesta :

Answer:

sec²-2scθ+tanθ+tan²θ=1-sinθ/1+sinθ

sec²-2scθ+tanθ+tan²θ

= 1+sin²θ-2sinθ/cos²θ

=-1+sinθ/1+sinθ

=1-sinθ/sinθ+1

1-sinθ/sinθ+1=-1+sinθ/1+sinθ True