Using a system of equations, it is found that 41 regular and 53 sleeper seat tickets were sold.
A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
In this problem, the variables are:
94 passengers rode in a train from City A to City B, hence:
[tex]x + y = 94[/tex]
Tickets for regular coach seats cost 115$. Tickets for sleeper cars seats cost 281$. The receipts for the trip totaled 19,608$, hence:
[tex]115x + 281y = 19608[/tex]
From the first equation, x = 94 - y, hence, replacing on the second.
[tex]115x + 281y = 19608[/tex]
[tex]115(94 - y) + 281y = 19608[/tex]
[tex]166y = 8798[/tex]
[tex]y = \frac{8798}{166}[/tex]
[tex]y = 53[/tex]
[tex]x = 94 - y = 94 - 53 = 41[/tex]
Hence, 41 regular and 53 sleeper seat tickets were sold.
To learn more about system of equations, you can take a look at https://brainly.com/question/14183076