Answer:
Slope intercept: y = -3/2x + 1
Point slope: y + 2 = -3/2 * (x - 2) [Forgot to add the work for this, I will add it if you need it, feel free to ask.]
Step-by-step explanation:
m = (change in y)/change in x)
But also
m = y_2 - y_1/x_2 - x_1
So lets substitute
m = 1 - (-2)/0 - (2)
Lets find the slope
m = 3/0 - (2)
m = 3/-2
m = -3/2 (Moved the negative)
Now we find the value of b using the equation of a line.
y = mx + b
y = (-3/2) * x + b
y = (-3/2) * (2) + b
-2 = (-3/2) * (2) + b
Now we find the value of b
Lets rewrite
-3/2 * 2 + b = -2
Cancel the CF of 2
-3 + b = -2
Move the terms without b to the right
b = -2 + 3
b = 1
Now we substitute our values of the slope and y-int into y = mx + b to find the equation.
y = -3/2x + 1
Answer:
[tex]y=\frac{-3}{2}x-1[/tex]
Step-by-step explanation:
Given the two points, we can use the slope formula to get the slope of our equation.
[tex]\frac{y_2-y_1}{x_2-x_1}=m[/tex]
Plug in what we know
[tex]\frac{(1)-(-2)}{0-2}=m[/tex]
[tex]m=\frac{-3}{2}[/tex]
[tex]y=\frac{-3}{2}x-b[/tex]
Plug in one of the points given and solve to find our y-intercept [b]
[tex]-2=\frac{-3}{2}(2)-b[/tex]
[tex]b=1[/tex]
(we already know our y-intercept since we're given what y is when x is 0 [hence (0,1)], but this is how it is done if we did not know it initially)
Final equation
[tex]y=\frac{-3}{2}x-1[/tex]
