The total rate of energy emission is 2786.9 W.
Radiation is a type of heat transfer where the heat energy is conveyed from photons or electromagnetic waves. The rate of energy emission can be calculated multiplying the Stefan–Boltzmann law (σ[tex]*T^4[/tex]) by area (A). Therefore, you have:
Total Rate of Energy Emission (E)= σ[tex]*A*T^4[/tex], where:
σ = Stefan–Boltzmann constant = [tex]5.67*10^{-8}[/tex] [tex]\frac{W}{m^2K^4}[/tex]
A= area
T=temperature (K)
For solving this exercise, you should apply this formula. For your question:
σ = Stefan–Boltzmann constant = [tex]5.67*10^{-8}[/tex] [tex]\frac{W}{m^2K^4}[/tex]
A= 0.12 m²
T=527+273=800 K
Thus, the Total Rate of Energy Emission (E) will be:
E=σ[tex]*A*T^4[/tex]
[tex]E=(5.67*10^{-8}\frac{W}{m^2K^4})*(0.12*m^{2} )*(800K)\\ \\ E=2786.9 W[/tex]
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